Base | Representation |
---|---|
bin | 10010001111111000010… |
… | …110011010111000111101 |
3 | 11102212210120012112110002 |
4 | 102033320112122320331 |
5 | 131021144020010023 |
6 | 2400025225124045 |
7 | 156412225031012 |
oct | 22177026327075 |
9 | 4385716175402 |
10 | 1254002110013 |
11 | 443901554684 |
12 | 18304a929625 |
13 | 91337537663 |
14 | 449a059b709 |
15 | 22945ac0b28 |
hex | 123f859ae3d |
1254002110013 has 2 divisors, whose sum is σ = 1254002110014. Its totient is φ = 1254002110012.
The previous prime is 1254002109953. The next prime is 1254002110027. The reversal of 1254002110013 is 3100112004521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 808896975769 + 445105134244 = 899387^2 + 667162^2 .
It is a cyclic number.
It is not a de Polignac number, because 1254002110013 - 220 = 1254001061437 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1254002110043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627001055006 + 627001055007.
It is an arithmetic number, because the mean of its divisors is an integer number (627001055007).
Almost surely, 21254002110013 is an apocalyptic number.
It is an amenable number.
1254002110013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1254002110013 is an equidigital number, since it uses as much as digits as its factorization.
1254002110013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 20.
Adding to 1254002110013 its reverse (3100112004521), we get a palindrome (4354114114534).
The spelling of 1254002110013 in words is "one trillion, two hundred fifty-four billion, two million, one hundred ten thousand, thirteen".
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