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12540200113 = 713912888181
BaseRepresentation
bin10111010110111010…
…00100010010110001
31012100221121011121001
423223131010102301
5201140242400423
65432204002001
7622520641120
oct135335042261
935327534531
1012540200113
115355685a51
12251b830301
13124b05356c
1486d679ab7
154d5dc9cad
hex2eb7444b1

12540200113 has 8 divisors (see below), whose sum is σ = 14434763840. Its totient is φ = 10671413040.

The previous prime is 12540200107. The next prime is 12540200117. The reversal of 12540200113 is 31100204521.

12540200113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12540200113 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12540200117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6443118 + ... + 6445063.

It is an arithmetic number, because the mean of its divisors is an integer number (1804345480).

Almost surely, 212540200113 is an apocalyptic number.

It is an amenable number.

12540200113 is a deficient number, since it is larger than the sum of its proper divisors (1894563727).

12540200113 is a wasteful number, since it uses less digits than its factorization.

12540200113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12888327.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 12540200113 its reverse (31100204521), we get a palindrome (43640404634).

The spelling of 12540200113 in words is "twelve billion, five hundred forty million, two hundred thousand, one hundred thirteen".

Divisors: 1 7 139 973 12888181 90217267 1791457159 12540200113