12540433 has 2 divisors, whose sum is σ = 12540434. Its totient is φ = 12540432.

The previous prime is 12540431. The next prime is 12540443. The reversal of 12540433 is 33404521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10712529 + 1827904 = 3273^2 + 1352^2 .

It is a cyclic number.

It is not a de Polignac number, because 12540433 - 2¹ = 12540431 is a prime.

Together with 12540431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (12540431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6270216 + 6270217.

It is an arithmetic number, because the mean of its divisors is an integer number (6270217).

Almost surely, 2^12540433 is an apocalyptic number.

It is an amenable number.

12540433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12540433 is an equidigital number, since it uses as much as digits as its factorization.

12540433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 12540433 is about 3541.2473791025. The cubic root of 12540433 is about 232.3294035103.

Adding to 12540433 its reverse (33404521), we get a palindrome (45944954).

The spelling of 12540433 in words is "twelve million, five hundred forty thousand, four hundred thirty-three".