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12541130254997 is a prime number
BaseRepresentation
bin1011011001111111010110…
…0111010010101010010101
31122101220211221010020220122
42312133311213102222111
53120433213321124442
642401152105241325
72433031620205631
oct266376547225225
948356757106818
1012541130254997
113aa573309a683
1214a667b193245
136cc814b04946
14314dcb545dc1
1516b35489add2
hexb67f59d2a95

12541130254997 has 2 divisors, whose sum is σ = 12541130254998. Its totient is φ = 12541130254996.

The previous prime is 12541130254973. The next prime is 12541130255029. The reversal of 12541130254997 is 79945203114521.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12071184358321 + 469945896676 = 3474361^2 + 685526^2 .

It is a cyclic number.

It is not a de Polignac number, because 12541130254997 - 234 = 12523950385813 is a prime.

It is a super-2 number, since 2×125411302549972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12541130254907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6270565127498 + 6270565127499.

It is an arithmetic number, because the mean of its divisors is an integer number (6270565127499).

Almost surely, 212541130254997 is an apocalyptic number.

It is an amenable number.

12541130254997 is a deficient number, since it is larger than the sum of its proper divisors (1).

12541130254997 is an equidigital number, since it uses as much as digits as its factorization.

12541130254997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2721600, while the sum is 53.

The spelling of 12541130254997 in words is "twelve trillion, five hundred forty-one billion, one hundred thirty million, two hundred fifty-four thousand, nine hundred ninety-seven".