Base | Representation |
---|---|
bin | 1011011010000111100011… |
… | …1111011110101100100000 |
3 | 1122102010112112121222120122 |
4 | 2312201320333132230200 |
5 | 3121002222102123130 |
6 | 42402154524055412 |
7 | 2433140343214556 |
oct | 266417077365440 |
9 | 48363475558518 |
10 | 12543334411040 |
11 | 3aa66642a8744 |
12 | 14a6b95394568 |
13 | 6ccaa665cba4 |
14 | 31515a185bd6 |
15 | 16b4331392e5 |
hex | b6878fdeb20 |
12543334411040 has 24 divisors (see below), whose sum is σ = 29633627546460. Its totient is φ = 5017333764352.
The previous prime is 12543334410941. The next prime is 12543334411043. The reversal of 12543334411040 is 4011443334521.
It can be written as a sum of positive squares in 2 ways, for example, as 12538596016144 + 4738394896 = 3540988^2 + 68836^2 .
It is not an unprimeable number, because it can be changed into a prime (12543334411043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39197919875 + ... + 39197920194.
Almost surely, 212543334411040 is an apocalyptic number.
12543334411040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12543334411040 is an abundant number, since it is smaller than the sum of its proper divisors (17090293135420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12543334411040 is an equidigital number, since it uses as much as digits as its factorization.
12543334411040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78395840084 (or 78395840076 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 12543334411040 its reverse (4011443334521), we get a palindrome (16554777745561).
The spelling of 12543334411040 in words is "twelve trillion, five hundred forty-three billion, three hundred thirty-four million, four hundred eleven thousand, forty".
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