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12543355093 is a prime number
BaseRepresentation
bin10111010111010010…
…00110100011010101
31012101011112110102011
423223221012203111
5201142044330333
65432355344221
7622556521243
oct135351064325
935334473364
1012543355093
115357440375
1225208b2071
13124b8b9609
1486dc5b793
154d62ee9cd
hex2eba468d5

12543355093 has 2 divisors, whose sum is σ = 12543355094. Its totient is φ = 12543355092.

The previous prime is 12543355091. The next prime is 12543355151. The reversal of 12543355093 is 39055334521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12254932804 + 288422289 = 110702^2 + 16983^2 .

It is a cyclic number.

It is not a de Polignac number, because 12543355093 - 21 = 12543355091 is a prime.

Together with 12543355091, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12543355091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6271677546 + 6271677547.

It is an arithmetic number, because the mean of its divisors is an integer number (6271677547).

Almost surely, 212543355093 is an apocalyptic number.

It is an amenable number.

12543355093 is a deficient number, since it is larger than the sum of its proper divisors (1).

12543355093 is an equidigital number, since it uses as much as digits as its factorization.

12543355093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243000, while the sum is 40.

The spelling of 12543355093 in words is "twelve billion, five hundred forty-three million, three hundred fifty-five thousand, ninety-three".