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125440500013 is a prime number
BaseRepresentation
bin111010011010011010…
…1100010000100101101
3102222210011102122110221
41310310311202010231
54023400232000023
6133343201131341
712030350441323
oct1646465420455
9388704378427
10125440500013
114922098a324
1220389929b51
13baa139784a
1460ddb11d13
1533e292085d
hex1d34d6212d

125440500013 has 2 divisors, whose sum is σ = 125440500014. Its totient is φ = 125440500012.

The previous prime is 125440499983. The next prime is 125440500037. The reversal of 125440500013 is 310005044521.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71997232329 + 53443267684 = 268323^2 + 231178^2 .

It is a cyclic number.

It is not a de Polignac number, because 125440500013 - 221 = 125438402861 is a prime.

It is a super-2 number, since 2×1254405000132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125440500313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62720250006 + 62720250007.

It is an arithmetic number, because the mean of its divisors is an integer number (62720250007).

Almost surely, 2125440500013 is an apocalyptic number.

It is an amenable number.

125440500013 is a deficient number, since it is larger than the sum of its proper divisors (1).

125440500013 is an equidigital number, since it uses as much as digits as its factorization.

125440500013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 125440500013 its reverse (310005044521), we get a palindrome (435445544534).

The spelling of 125440500013 in words is "one hundred twenty-five billion, four hundred forty million, five hundred thousand, thirteen".