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125453440015 = 525090688003
BaseRepresentation
bin111010011010110011…
…0111001010000001111
3102222211001210001211021
41310311212321100033
54023412040040030
6133344342335011
712030565434301
oct1646546712017
9388731701737
10125453440015
1149228218342
122039212a467
13baa3c78657
14610171d971
1533e3b2997a
hex1d359b940f

125453440015 has 4 divisors (see below), whose sum is σ = 150544128024. Its totient is φ = 100362752008.

The previous prime is 125453439997. The next prime is 125453440051. The reversal of 125453440015 is 510044354521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 125453440015 - 217 = 125453308943 is a prime.

It is a super-2 number, since 2×1254534400152 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12545343997 + ... + 12545344006.

It is an arithmetic number, because the mean of its divisors is an integer number (37636032006).

Almost surely, 2125453440015 is an apocalyptic number.

125453440015 is a deficient number, since it is larger than the sum of its proper divisors (25090688009).

125453440015 is an equidigital number, since it uses as much as digits as its factorization.

125453440015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25090688008.

The product of its (nonzero) digits is 48000, while the sum is 34.

Adding to 125453440015 its reverse (510044354521), we get a palindrome (635497794536).

The spelling of 125453440015 in words is "one hundred twenty-five billion, four hundred fifty-three million, four hundred forty thousand, fifteen".

Divisors: 1 5 25090688003 125453440015