Base | Representation |
---|---|
bin | 1011011010001111011000… |
… | …1001101000101010111111 |
3 | 1122102022221212210121021202 |
4 | 2312203312021220222333 |
5 | 3121021022130202333 |
6 | 42403143134250115 |
7 | 2433243361306265 |
oct | 266436611505277 |
9 | 48368855717252 |
10 | 12545434225343 |
11 | 3aa754161a268 |
12 | 14a748065693b |
13 | 70004c6b4366 |
14 | 3152b8dc4435 |
15 | 16b5076665e8 |
hex | b68f6268abf |
12545434225343 has 4 divisors (see below), whose sum is σ = 12577684699320. Its totient is φ = 12513183751368.
The previous prime is 12545434225339. The next prime is 12545434225349. The reversal of 12545434225343 is 34352243454521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12545434225343 - 22 = 12545434225339 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12545434225349) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16125236405 + ... + 16125237182.
It is an arithmetic number, because the mean of its divisors is an integer number (3144421174830).
Almost surely, 212545434225343 is an apocalyptic number.
12545434225343 is a deficient number, since it is larger than the sum of its proper divisors (32250473977).
12545434225343 is an equidigital number, since it uses as much as digits as its factorization.
12545434225343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32250473976.
The product of its digits is 6912000, while the sum is 47.
Adding to 12545434225343 its reverse (34352243454521), we get a palindrome (46897677679864).
The spelling of 12545434225343 in words is "twelve trillion, five hundred forty-five billion, four hundred thirty-four million, two hundred twenty-five thousand, three hundred forty-three".
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