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1255440434001 = 31332190780359
BaseRepresentation
bin10010010001001110000…
…101001100001101010001
311110000111210122222000220
4102101032011030031101
5131032120222342001
62400424045303253
7156462661421265
oct22211605141521
94400453588026
101255440434001
1144447a439796
12183390564b29
1391506513b40
1444a996080a5
15229cbed5c36
hex1244e14c351

1255440434001 has 8 divisors (see below), whose sum is σ = 1802683700160. Its totient is φ = 772578728592.

The previous prime is 1255440433997. The next prime is 1255440434033. The reversal of 1255440434001 is 1004340445521.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1255440434001 - 22 = 1255440433997 is a prime.

It is a super-2 number, since 2×12554404340012 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1255440434041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16095390141 + ... + 16095390218.

It is an arithmetic number, because the mean of its divisors is an integer number (225335462520).

Almost surely, 21255440434001 is an apocalyptic number.

It is an amenable number.

1255440434001 is a deficient number, since it is larger than the sum of its proper divisors (547243266159).

1255440434001 is a wasteful number, since it uses less digits than its factorization.

1255440434001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32190780375.

The product of its (nonzero) digits is 38400, while the sum is 33.

Adding to 1255440434001 its reverse (1004340445521), we get a palindrome (2259780879522).

The spelling of 1255440434001 in words is "one trillion, two hundred fifty-five billion, four hundred forty million, four hundred thirty-four thousand, one".

Divisors: 1 3 13 39 32190780359 96572341077 418480144667 1255440434001