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1256050407253 is a prime number
BaseRepresentation
bin10010010001110010011…
…100000011011101010101
311110002002022102211000211
4102101302130003131111
5131034342401013003
62401004355205421
7156514046206045
oct22216234033525
94402068384024
101256050407253
11444762789714
121835208a6871
13915a29c2065
1444b16629725
1522a1582396d
hex12472703755

1256050407253 has 2 divisors, whose sum is σ = 1256050407254. Its totient is φ = 1256050407252.

The previous prime is 1256050407247. The next prime is 1256050407259. The reversal of 1256050407253 is 3527040506521.

It is a balanced prime because it is at equal distance from previous prime (1256050407247) and next prime (1256050407259).

It can be written as a sum of positive squares in only one way, i.e., 787562177809 + 468488229444 = 887447^2 + 684462^2 .

It is a cyclic number.

It is not a de Polignac number, because 1256050407253 - 229 = 1255513536341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1256050407259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 628025203626 + 628025203627.

It is an arithmetic number, because the mean of its divisors is an integer number (628025203627).

Almost surely, 21256050407253 is an apocalyptic number.

It is an amenable number.

1256050407253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1256050407253 is an equidigital number, since it uses as much as digits as its factorization.

1256050407253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252000, while the sum is 40.

The spelling of 1256050407253 in words is "one trillion, two hundred fifty-six billion, fifty million, four hundred seven thousand, two hundred fifty-three".