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125639011327 is a prime number
BaseRepresentation
bin111010100000010101…
…0110010101111111111
3110000021222222001210211
41311000222302233333
54024302041330302
6133415012013251
712035310655444
oct1650052625777
9400258861724
10125639011327
1149312a45865
1220424301227
13bb0355036b
14611c2279cb
153405083ad7
hex1d40ab2bff

125639011327 has 2 divisors, whose sum is σ = 125639011328. Its totient is φ = 125639011326.

The previous prime is 125639011313. The next prime is 125639011397. The reversal of 125639011327 is 723110936521.

It is a weak prime.

It is an emirp because it is prime and its reverse (723110936521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125639011327 is a prime.

It is a super-2 number, since 2×1256390113272 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 125639011327.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125639011397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62819505663 + 62819505664.

It is an arithmetic number, because the mean of its divisors is an integer number (62819505664).

Almost surely, 2125639011327 is an apocalyptic number.

125639011327 is a deficient number, since it is larger than the sum of its proper divisors (1).

125639011327 is an equidigital number, since it uses as much as digits as its factorization.

125639011327 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68040, while the sum is 40.

Adding to 125639011327 its reverse (723110936521), we get a palindrome (848749947848).

The spelling of 125639011327 in words is "one hundred twenty-five billion, six hundred thirty-nine million, eleven thousand, three hundred twenty-seven".