Base | Representation |
---|---|
bin | 111010100000010101… |
… | …0110010110001000101 |
3 | 110000021222222001220102 |
4 | 1311000222302301011 |
5 | 4024302041331042 |
6 | 133415012013445 |
7 | 12035310655604 |
oct | 1650052626105 |
9 | 400258861812 |
10 | 125639011397 |
11 | 49312a45919 |
12 | 20424301285 |
13 | bb035503c3 |
14 | 611c227a3b |
15 | 3405083b32 |
hex | 1d40ab2c45 |
125639011397 has 2 divisors, whose sum is σ = 125639011398. Its totient is φ = 125639011396.
The previous prime is 125639011327. The next prime is 125639011417. The reversal of 125639011397 is 793110936521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 88146047236 + 37492964161 = 296894^2 + 193631^2 .
It is a cyclic number.
It is not a de Polignac number, because 125639011397 - 222 = 125634817093 is a prime.
It is a super-2 number, since 2×1256390113972 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125639011327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62819505698 + 62819505699.
It is an arithmetic number, because the mean of its divisors is an integer number (62819505699).
Almost surely, 2125639011397 is an apocalyptic number.
It is an amenable number.
125639011397 is a deficient number, since it is larger than the sum of its proper divisors (1).
125639011397 is an equidigital number, since it uses as much as digits as its factorization.
125639011397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 306180, while the sum is 47.
The spelling of 125639011397 in words is "one hundred twenty-five billion, six hundred thirty-nine million, eleven thousand, three hundred ninety-seven".
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