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125639011397 is a prime number
BaseRepresentation
bin111010100000010101…
…0110010110001000101
3110000021222222001220102
41311000222302301011
54024302041331042
6133415012013445
712035310655604
oct1650052626105
9400258861812
10125639011397
1149312a45919
1220424301285
13bb035503c3
14611c227a3b
153405083b32
hex1d40ab2c45

125639011397 has 2 divisors, whose sum is σ = 125639011398. Its totient is φ = 125639011396.

The previous prime is 125639011327. The next prime is 125639011417. The reversal of 125639011397 is 793110936521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88146047236 + 37492964161 = 296894^2 + 193631^2 .

It is a cyclic number.

It is not a de Polignac number, because 125639011397 - 222 = 125634817093 is a prime.

It is a super-2 number, since 2×1256390113972 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125639011327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62819505698 + 62819505699.

It is an arithmetic number, because the mean of its divisors is an integer number (62819505699).

Almost surely, 2125639011397 is an apocalyptic number.

It is an amenable number.

125639011397 is a deficient number, since it is larger than the sum of its proper divisors (1).

125639011397 is an equidigital number, since it uses as much as digits as its factorization.

125639011397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 306180, while the sum is 47.

The spelling of 125639011397 in words is "one hundred twenty-five billion, six hundred thirty-nine million, eleven thousand, three hundred ninety-seven".