Base | Representation |
---|---|
bin | 111010100001010000… |
… | …1100010010000000011 |
3 | 110000101011112111210021 |
4 | 1311002201202100003 |
5 | 4024333023421013 |
6 | 133422043114311 |
7 | 12036136361362 |
oct | 1650241422003 |
9 | 400334474707 |
10 | 125670138883 |
11 | 49329576413 |
12 | 20432812997 |
13 | bb09b2b633 |
14 | 612240b7d9 |
15 | 3407b81a8d |
hex | 1d42862403 |
125670138883 has 2 divisors, whose sum is σ = 125670138884. Its totient is φ = 125670138882.
The previous prime is 125670138851. The next prime is 125670138911. The reversal of 125670138883 is 388831076521.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 125670138883 - 25 = 125670138851 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 125670138883.
It is not a weakly prime, because it can be changed into another prime (125670138983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62835069441 + 62835069442.
It is an arithmetic number, because the mean of its divisors is an integer number (62835069442).
Almost surely, 2125670138883 is an apocalyptic number.
125670138883 is a deficient number, since it is larger than the sum of its proper divisors (1).
125670138883 is an equidigital number, since it uses as much as digits as its factorization.
125670138883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1935360, while the sum is 52.
The spelling of 125670138883 in words is "one hundred twenty-five billion, six hundred seventy million, one hundred thirty-eight thousand, eight hundred eighty-three".
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