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1257075431 is a prime number
BaseRepresentation
bin100101011101101…
…0111001011100111
310020121102001022022
41022323113023213
510033302403211
6324423253355
743102651643
oct11273271347
93217361268
101257075431
1159564a417
122b0baa25b
13170589221
14bcd49c23
1575561bdb
hex4aed72e7

1257075431 has 2 divisors, whose sum is σ = 1257075432. Its totient is φ = 1257075430.

The previous prime is 1257075367. The next prime is 1257075433. The reversal of 1257075431 is 1345707521.

It is a strong prime.

It is an emirp because it is prime and its reverse (1345707521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1257075431 - 26 = 1257075367 is a prime.

It is a super-2 number, since 2×12570754312 = 3160477278447671522, which contains 22 as substring.

Together with 1257075433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1257075391 and 1257075400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1257075433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 628537715 + 628537716.

It is an arithmetic number, because the mean of its divisors is an integer number (628537716).

Almost surely, 21257075431 is an apocalyptic number.

1257075431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1257075431 is an equidigital number, since it uses as much as digits as its factorization.

1257075431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 29400, while the sum is 35.

The square root of 1257075431 is about 35455.2595675169. The cubic root of 1257075431 is about 1079.2459960613.

The spelling of 1257075431 in words is "one billion, two hundred fifty-seven million, seventy-five thousand, four hundred thirty-one".