12573401626477 has 4 divisors (see below), whose sum is σ = 13313013486876. Its totient is φ = 11833789766080.

The previous prime is 12573401626447. The next prime is 12573401626493. The reversal of 12573401626477 is 77462610437521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5522565800196 + 7050835826281 = 2350014^2 + 2655341^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12573401626477 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12573401626447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 369805930174 + ... + 369805930207.

It is an arithmetic number, because the mean of its divisors is an integer number (3328253371719).

Almost surely, 2^{12573401626477} is an apocalyptic number.

12573401626477 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

It is an amenable number.

12573401626477 is a deficient number, since it is larger than the sum of its proper divisors (739611860399).

12573401626477 is an equidigital number, since it uses as much as digits as its factorization.

12573401626477 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 739611860398.

The product of its (nonzero) digits is 11854080, while the sum is 55.

The spelling of 12573401626477 in words is "twelve trillion, five hundred seventy-three billion, four hundred one million, six hundred twenty-six thousand, four hundred seventy-seven".