Base | Representation |
---|---|
bin | 10111011011010110… |
… | …01000111111111111 |
3 | 1012110112200100101022 |
4 | 23231223020333333 |
5 | 201224311200324 |
6 | 5440014134355 |
7 | 623452336322 |
oct | 135553107777 |
9 | 35415610338 |
10 | 12577443839 |
11 | 5374703794 |
12 | 25301b13bb |
13 | 125599367c |
14 | 8745b27b9 |
15 | 4d92d505e |
hex | 2edac8fff |
12577443839 has 2 divisors, whose sum is σ = 12577443840. Its totient is φ = 12577443838.
The previous prime is 12577443821. The next prime is 12577443841. The reversal of 12577443839 is 93834477521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12577443839 - 220 = 12576395263 is a prime.
It is a Sophie Germain prime.
Together with 12577443841, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12577443859) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6288721919 + 6288721920.
It is an arithmetic number, because the mean of its divisors is an integer number (6288721920).
Almost surely, 212577443839 is an apocalyptic number.
12577443839 is a deficient number, since it is larger than the sum of its proper divisors (1).
12577443839 is an equidigital number, since it uses as much as digits as its factorization.
12577443839 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5080320, while the sum is 53.
The spelling of 12577443839 in words is "twelve billion, five hundred seventy-seven million, four hundred forty-three thousand, eight hundred thirty-nine".
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