Base | Representation |
---|---|
bin | 10010010101111100001… |
… | …100001000010001000111 |
3 | 11110111121001000101012022 |
4 | 102111330030020101013 |
5 | 131123010244101403 |
6 | 2403023025513355 |
7 | 160032405323303 |
oct | 22257414102107 |
9 | 4414531011168 |
10 | 1260508972103 |
11 | 4466404a9457 |
12 | 184365aa285b |
13 | 91b3361ba04 |
14 | 4501a82ad03 |
15 | 22bc6e79d38 |
hex | 1257c308447 |
1260508972103 has 2 divisors, whose sum is σ = 1260508972104. Its totient is φ = 1260508972102.
The previous prime is 1260508972039. The next prime is 1260508972117. The reversal of 1260508972103 is 3012798050621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1260508972103 - 26 = 1260508972039 is a prime.
It is a super-3 number, since 3×12605089721033 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1260508972133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 630254486051 + 630254486052.
It is an arithmetic number, because the mean of its divisors is an integer number (630254486052).
Almost surely, 21260508972103 is an apocalyptic number.
1260508972103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1260508972103 is an equidigital number, since it uses as much as digits as its factorization.
1260508972103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 44.
The spelling of 1260508972103 in words is "one trillion, two hundred sixty billion, five hundred eight million, nine hundred seventy-two thousand, one hundred three".
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