Base | Representation |
---|---|
bin | 1011011110001000110110… |
… | …1111101000100000100111 |
3 | 1122122201210222120211200201 |
4 | 2313202031233220200213 |
5 | 3123120144411231312 |
6 | 42454020231251331 |
7 | 2441134036415623 |
oct | 267421557504047 |
9 | 48581728524621 |
10 | 12612402055207 |
11 | 4022987178aa9 |
12 | 14b844bb19b47 |
13 | 7064628927a6 |
14 | 31862d01c183 |
15 | 16d12697b557 |
hex | b788dbe8827 |
12612402055207 has 2 divisors, whose sum is σ = 12612402055208. Its totient is φ = 12612402055206.
The previous prime is 12612402055129. The next prime is 12612402055237. The reversal of 12612402055207 is 70255020421621.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12612402055207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12612402055237) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6306201027603 + 6306201027604.
It is an arithmetic number, because the mean of its divisors is an integer number (6306201027604).
Almost surely, 212612402055207 is an apocalyptic number.
12612402055207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12612402055207 is an equidigital number, since it uses as much as digits as its factorization.
12612402055207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67200, while the sum is 37.
Adding to 12612402055207 its reverse (70255020421621), we get a palindrome (82867422476828).
The spelling of 12612402055207 in words is "twelve trillion, six hundred twelve billion, four hundred two million, fifty-five thousand, two hundred seven".
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