Base | Representation |
---|---|
bin | 10111100001101100… |
… | …00010110010101011 |
3 | 1012121020202200002001 |
4 | 23300312002302223 |
5 | 201331420234033 |
6 | 5445154151431 |
7 | 624666420535 |
oct | 136066026253 |
9 | 35536680061 |
10 | 12630633643 |
11 | 53a1733001 |
12 | 2545b82577 |
13 | 12639c7924 |
14 | 87b69a855 |
15 | 4ddcdee7d |
hex | 2f0d82cab |
12630633643 has 2 divisors, whose sum is σ = 12630633644. Its totient is φ = 12630633642.
The previous prime is 12630633641. The next prime is 12630633677. The reversal of 12630633643 is 34633603621.
12630633643 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (34633603621) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12630633643 - 21 = 12630633641 is a prime.
Together with 12630633641, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12630633641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6315316821 + 6315316822.
It is an arithmetic number, because the mean of its divisors is an integer number (6315316822).
Almost surely, 212630633643 is an apocalyptic number.
12630633643 is a deficient number, since it is larger than the sum of its proper divisors (1).
12630633643 is an equidigital number, since it uses as much as digits as its factorization.
12630633643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 37.
The spelling of 12630633643 in words is "twelve billion, six hundred thirty million, six hundred thirty-three thousand, six hundred forty-three".
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