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126315113 is a prime number
BaseRepresentation
bin1111000011101…
…10101001101001
322210200110202112
413201312221221
5224314040423
620311212105
73062442431
oct741665151
9283613675
10126315113
1165335461
1236377035
1320228492
1412ac12c1
15b151a78
hex7876a69

126315113 has 2 divisors, whose sum is σ = 126315114. Its totient is φ = 126315112.

The previous prime is 126315073. The next prime is 126315131. The reversal of 126315113 is 311513621.

Together with next prime (126315131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126270169 + 44944 = 11237^2 + 212^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-126315113 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (126315613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63157556 + 63157557.

It is an arithmetic number, because the mean of its divisors is an integer number (63157557).

Almost surely, 2126315113 is an apocalyptic number.

It is an amenable number.

126315113 is a deficient number, since it is larger than the sum of its proper divisors (1).

126315113 is an equidigital number, since it uses as much as digits as its factorization.

126315113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 540, while the sum is 23.

The square root of 126315113 is about 11238.9996440964. Note that the first 3 decimals coincide. The cubic root of 126315113 is about 501.7473702805.

Adding to 126315113 its reverse (311513621), we get a palindrome (437828734).

The spelling of 126315113 in words is "one hundred twenty-six million, three hundred fifteen thousand, one hundred thirteen".