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126315131 is a prime number
BaseRepresentation
bin1111000011101…
…10101001111011
322210200110210012
413201312221323
5224314041011
620311212135
73062442455
oct741665173
9283613705
10126315131
1165335478
123637704b
13202284a7
1412ac12d5
15b151a8b
hex7876a7b

126315131 has 2 divisors, whose sum is σ = 126315132. Its totient is φ = 126315130.

The previous prime is 126315113. The next prime is 126315139. The reversal of 126315131 is 131513621.

Together with previous prime (126315113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 126315131 - 210 = 126314107 is a prime.

It is a super-2 number, since 2×1263151312 = 31911024639094322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 126315097 and 126315106.

It is not a weakly prime, because it can be changed into another prime (126315139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63157565 + 63157566.

It is an arithmetic number, because the mean of its divisors is an integer number (63157566).

Almost surely, 2126315131 is an apocalyptic number.

126315131 is a deficient number, since it is larger than the sum of its proper divisors (1).

126315131 is an equidigital number, since it uses as much as digits as its factorization.

126315131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 540, while the sum is 23.

The square root of 126315131 is about 11239.0004448794. Note that the first 3 decimals coincide. The cubic root of 126315131 is about 501.7473941137.

Adding to 126315131 its reverse (131513621), we get a palindrome (257828752).

The spelling of 126315131 in words is "one hundred twenty-six million, three hundred fifteen thousand, one hundred thirty-one".