Base | Representation |
---|---|
bin | 111010110101010000… |
… | …1111110101100101111 |
3 | 110002002221112021011210 |
4 | 1311222201332230233 |
5 | 4032221341002142 |
6 | 134012421245503 |
7 | 12061566463632 |
oct | 1655241765457 |
9 | 402087467153 |
10 | 126341344047 |
11 | 49643438826 |
12 | 2059b563893 |
13 | bbb5bc8459 |
14 | 618760bc19 |
15 | 3446a6749c |
hex | 1d6a87eb2f |
126341344047 has 4 divisors (see below), whose sum is σ = 168455125400. Its totient is φ = 84227562696.
The previous prime is 126341344033. The next prime is 126341344049. The reversal of 126341344047 is 740443143621.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 126341344047 - 215 = 126341311279 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 126341343996 and 126341344014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (126341344049) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21056890672 + ... + 21056890677.
It is an arithmetic number, because the mean of its divisors is an integer number (42113781350).
Almost surely, 2126341344047 is an apocalyptic number.
126341344047 is a deficient number, since it is larger than the sum of its proper divisors (42113781353).
126341344047 is an equidigital number, since it uses as much as digits as its factorization.
126341344047 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42113781352.
The product of its (nonzero) digits is 193536, while the sum is 39.
Adding to 126341344047 its reverse (740443143621), we get a palindrome (866784487668).
The spelling of 126341344047 in words is "one hundred twenty-six billion, three hundred forty-one million, three hundred forty-four thousand, forty-seven".
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