Base | Representation |
---|---|
bin | 111010110111000001… |
… | …1101010011000100111 |
3 | 110002021001211222021101 |
4 | 1311232003222120213 |
5 | 4032332012133013 |
6 | 134022333300531 |
7 | 12063215365645 |
oct | 1655603523047 |
9 | 402231758241 |
10 | 126400505383 |
11 | 49673876599 |
12 | 205b7334747 |
13 | bbc5240769 |
14 | 619140c195 |
15 | 344bd518dd |
hex | 1d6e0ea627 |
126400505383 has 2 divisors, whose sum is σ = 126400505384. Its totient is φ = 126400505382.
The previous prime is 126400505351. The next prime is 126400505417. The reversal of 126400505383 is 383505004621.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 126400505383 - 25 = 126400505351 is a prime.
It is a super-2 number, since 2×1264005053832 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126400505303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63200252691 + 63200252692.
It is an arithmetic number, because the mean of its divisors is an integer number (63200252692).
Almost surely, 2126400505383 is an apocalyptic number.
126400505383 is a deficient number, since it is larger than the sum of its proper divisors (1).
126400505383 is an equidigital number, since it uses as much as digits as its factorization.
126400505383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 126400505383 in words is "one hundred twenty-six billion, four hundred million, five hundred five thousand, three hundred eighty-three".
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