Base | Representation |
---|---|
bin | 111010110111000001… |
… | …1101010011000000111 |
3 | 110002021001211222020012 |
4 | 1311232003222120013 |
5 | 4032332012132401 |
6 | 134022333300435 |
7 | 12063215365601 |
oct | 1655603523007 |
9 | 402231758205 |
10 | 126400505351 |
11 | 4967387656a |
12 | 205b733471b |
13 | bbc5240743 |
14 | 619140c171 |
15 | 344bd518bb |
hex | 1d6e0ea607 |
126400505351 has 2 divisors, whose sum is σ = 126400505352. Its totient is φ = 126400505350.
The previous prime is 126400505327. The next prime is 126400505383. The reversal of 126400505351 is 153505004621.
It is an a-pointer prime, because the next prime (126400505383) can be obtained adding 126400505351 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 126400505351 - 222 = 126396311047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126400565351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63200252675 + 63200252676.
It is an arithmetic number, because the mean of its divisors is an integer number (63200252676).
Almost surely, 2126400505351 is an apocalyptic number.
126400505351 is a deficient number, since it is larger than the sum of its proper divisors (1).
126400505351 is an equidigital number, since it uses as much as digits as its factorization.
126400505351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 126400505351 its reverse (153505004621), we get a palindrome (279905509972).
The spelling of 126400505351 in words is "one hundred twenty-six billion, four hundred million, five hundred five thousand, three hundred fifty-one".
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