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12651251303 is a prime number
BaseRepresentation
bin10111100100001001…
…01100011001100111
31012122200120011012002
423302010230121213
5201402210020203
65451212115515
7625336601405
oct136204543147
935580504162
1012651251303
115402335399
122550a65b9b
131268066222
14880306475
154e0a13d88
hex2f212c667

12651251303 has 2 divisors, whose sum is σ = 12651251304. Its totient is φ = 12651251302.

The previous prime is 12651251243. The next prime is 12651251317. The reversal of 12651251303 is 30315215621.

12651251303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (30315215621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12651251303 - 214 = 12651234919 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12656251303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6325625651 + 6325625652.

It is an arithmetic number, because the mean of its divisors is an integer number (6325625652).

Almost surely, 212651251303 is an apocalyptic number.

12651251303 is a deficient number, since it is larger than the sum of its proper divisors (1).

12651251303 is an equidigital number, since it uses as much as digits as its factorization.

12651251303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 12651251303 its reverse (30315215621), we get a palindrome (42966466924).

The spelling of 12651251303 in words is "twelve billion, six hundred fifty-one million, two hundred fifty-one thousand, three hundred three".