Base | Representation |
---|---|
bin | 1011100001100111000000… |
… | …0100101101100011000111 |
3 | 1122212102201211020200020020 |
4 | 2320121300010231203013 |
5 | 3130104311123302120 |
6 | 42541241342510223 |
7 | 2445344545063215 |
oct | 270316004554307 |
9 | 48772654220206 |
10 | 12672033806535 |
11 | 40461a77a7414 |
12 | 1507b12595373 |
13 | 70bc76c4754c |
14 | 31b488a13cb5 |
15 | 16e966bdd640 |
hex | b867012d8c7 |
12672033806535 has 8 divisors (see below), whose sum is σ = 20275254090480. Its totient is φ = 6758418030144.
The previous prime is 12672033806519. The next prime is 12672033806557. The reversal of 12672033806535 is 53560833027621.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12672033806535 - 24 = 12672033806519 is a prime.
It is a super-3 number, since 3×126720338065353 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 422401126870 + ... + 422401126899.
It is an arithmetic number, because the mean of its divisors is an integer number (2534406761310).
Almost surely, 212672033806535 is an apocalyptic number.
12672033806535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12672033806535 is a deficient number, since it is larger than the sum of its proper divisors (7603220283945).
12672033806535 is an equidigital number, since it uses as much as digits as its factorization.
12672033806535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 844802253777.
The product of its (nonzero) digits is 5443200, while the sum is 51.
The spelling of 12672033806535 in words is "twelve trillion, six hundred seventy-two billion, thirty-three million, eight hundred six thousand, five hundred thirty-five".
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