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127042169053 is a prime number
BaseRepresentation
bin111011001010001001…
…1011010100011011101
3110010220210020212100111
41312110103122203131
54040140243402203
6134210134330021
712115136422342
oct1662423324335
9403823225314
10127042169053
1149972aa0a48
12207561b9911
13bc981661c7
14621271c7c9
15348834e26d
hex1d944da8dd

127042169053 has 2 divisors, whose sum is σ = 127042169054. Its totient is φ = 127042169052.

The previous prime is 127042168987. The next prime is 127042169063. The reversal of 127042169053 is 350961240721.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91289788164 + 35752380889 = 302142^2 + 189083^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-127042169053 is a prime.

It is a super-2 number, since 2×1270421690532 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 127042168997 and 127042169015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (127042169063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63521084526 + 63521084527.

It is an arithmetic number, because the mean of its divisors is an integer number (63521084527).

Almost surely, 2127042169053 is an apocalyptic number.

It is an amenable number.

127042169053 is a deficient number, since it is larger than the sum of its proper divisors (1).

127042169053 is an equidigital number, since it uses as much as digits as its factorization.

127042169053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90720, while the sum is 40.

The spelling of 127042169053 in words is "one hundred twenty-seven billion, forty-two million, one hundred sixty-nine thousand, fifty-three".