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12713302051 = 103123430117
BaseRepresentation
bin10111101011100010…
…11001100000100011
31012211000022122210221
423311301121200203
5202014101131201
65501310103511
7630022166362
oct136561314043
935730278727
1012713302051
115434366aaa
1225697aab97
131277b80748
148886597d9
154e61be4a1
hex2f5c59823

12713302051 has 4 divisors (see below), whose sum is σ = 12836732272. Its totient is φ = 12589871832.

The previous prime is 12713302037. The next prime is 12713302061. The reversal of 12713302051 is 15020331721.

It is a happy number.

12713302051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12713302051 - 211 = 12713300003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12713302061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61714956 + ... + 61715161.

It is an arithmetic number, because the mean of its divisors is an integer number (3209183068).

Almost surely, 212713302051 is an apocalyptic number.

12713302051 is a deficient number, since it is larger than the sum of its proper divisors (123430221).

12713302051 is a wasteful number, since it uses less digits than its factorization.

12713302051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123430220.

The product of its (nonzero) digits is 1260, while the sum is 25.

Adding to 12713302051 its reverse (15020331721), we get a palindrome (27733633772).

The spelling of 12713302051 in words is "twelve billion, seven hundred thirteen million, three hundred two thousand, fifty-one".

Divisors: 1 103 123430117 12713302051