Base | Representation |
---|---|
bin | 1011100100000000111111… |
… | …1011011011000000110111 |
3 | 1200000101102122101210112122 |
4 | 2321000033323123000313 |
5 | 3131243440312302133 |
6 | 43012235230110155 |
7 | 2451340112435015 |
oct | 271001773330067 |
9 | 50011378353478 |
10 | 12713370431543 |
11 | 406178a198621 |
12 | 1513b2a04b35b |
13 | 712b33bb9382 |
14 | 31d48a9178b5 |
15 | 170a85bec498 |
hex | b900fedb037 |
12713370431543 has 4 divisors (see below), whose sum is σ = 12713388666600. Its totient is φ = 12713352196488.
The previous prime is 12713370431537. The next prime is 12713370431591. The reversal of 12713370431543 is 34513407331721.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12713370431543 - 26 = 12713370431479 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12713370431494 and 12713370431503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12713370431513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8028368 + ... + 9480581.
It is an arithmetic number, because the mean of its divisors is an integer number (3178347166650).
Almost surely, 212713370431543 is an apocalyptic number.
12713370431543 is a deficient number, since it is larger than the sum of its proper divisors (18235057).
12713370431543 is an equidigital number, since it uses as much as digits as its factorization.
12713370431543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18235056.
The product of its (nonzero) digits is 635040, while the sum is 44.
The spelling of 12713370431543 in words is "twelve trillion, seven hundred thirteen billion, three hundred seventy million, four hundred thirty-one thousand, five hundred forty-three".
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