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127146238493 is a prime number
BaseRepresentation
bin111011001101010000…
…0011010001000011101
3110011012001002010210012
41312122200122020131
54040343414112433
6134224333053005
712120542123651
oct1663240321035
9404161063705
10127146238493
1149a1681194a
1220785027165
13bcb38a3061
14622248ca61
153492559848
hex1d9a81a21d

127146238493 has 2 divisors, whose sum is σ = 127146238494. Its totient is φ = 127146238492.

The previous prime is 127146238487. The next prime is 127146238507. The reversal of 127146238493 is 394832641721.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119811515044 + 7334723449 = 346138^2 + 85643^2 .

It is a cyclic number.

It is not a de Polignac number, because 127146238493 - 210 = 127146237469 is a prime.

It is a super-2 number, since 2×1271462384932 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (127146238423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63573119246 + 63573119247.

It is an arithmetic number, because the mean of its divisors is an integer number (63573119247).

Almost surely, 2127146238493 is an apocalyptic number.

It is an amenable number.

127146238493 is a deficient number, since it is larger than the sum of its proper divisors (1).

127146238493 is an equidigital number, since it uses as much as digits as its factorization.

127146238493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1741824, while the sum is 50.

The spelling of 127146238493 in words is "one hundred twenty-seven billion, one hundred forty-six million, two hundred thirty-eight thousand, four hundred ninety-three".