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12715486461173 is a prime number
BaseRepresentation
bin1011100100001000111000…
…0011011011110011110101
31200000120220010002020111102
42321002032003123303311
53131312304013224143
643013225220015445
72451443415413426
oct271021603336365
950016803066442
1012715486461173
114062675684a41
12151441a831585
137130b03ca402
1431d60b97764d
15170b5b87e0b8
hexb908e0dbcf5

12715486461173 has 2 divisors, whose sum is σ = 12715486461174. Its totient is φ = 12715486461172.

The previous prime is 12715486461133. The next prime is 12715486461187. The reversal of 12715486461173 is 37116468451721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7720829135044 + 4994657326129 = 2778638^2 + 2234873^2 .

It is an emirp because it is prime and its reverse (37116468451721) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12715486461173 - 218 = 12715486199029 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12715486461113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6357743230586 + 6357743230587.

It is an arithmetic number, because the mean of its divisors is an integer number (6357743230587).

Almost surely, 212715486461173 is an apocalyptic number.

It is an amenable number.

12715486461173 is a deficient number, since it is larger than the sum of its proper divisors (1).

12715486461173 is an equidigital number, since it uses as much as digits as its factorization.

12715486461173 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6773760, while the sum is 56.

The spelling of 12715486461173 in words is "twelve trillion, seven hundred fifteen billion, four hundred eighty-six million, four hundred sixty-one thousand, one hundred seventy-three".