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12716506515703 = 43912896038833
BaseRepresentation
bin1011100100001100101011…
…0110101000100011110111
31200000200112012111101020211
42321003022312220203313
53131321401132000303
643013514335210251
72451510612631354
oct271031266504367
950020465441224
1012716506515703
114063049456011
121514664376987
13713213839783
1431d6a722562b
15170bbb1c266d
hexb90cada88f7

12716506515703 has 4 divisors (see below), whose sum is σ = 12719402558928. Its totient is φ = 12713610472480.

The previous prime is 12716506515679. The next prime is 12716506515851. The reversal of 12716506515703 is 30751560561721.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12716506515703 - 221 = 12716504418551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12716506525703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1448015026 + ... + 1448023807.

It is an arithmetic number, because the mean of its divisors is an integer number (3179850639732).

Almost surely, 212716506515703 is an apocalyptic number.

12716506515703 is a deficient number, since it is larger than the sum of its proper divisors (2896043225).

12716506515703 is an equidigital number, since it uses as much as digits as its factorization.

12716506515703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2896043224.

The product of its (nonzero) digits is 1323000, while the sum is 49.

The spelling of 12716506515703 in words is "twelve trillion, seven hundred sixteen billion, five hundred six million, five hundred fifteen thousand, seven hundred three".

Divisors: 1 4391 2896038833 12716506515703