Base | Representation |
---|---|
bin | 10010100000101111000… |
… | …101111011101110000111 |
3 | 11111121111212100010121121 |
4 | 102200233011323232013 |
5 | 131320230200412403 |
6 | 2412221142254411 |
7 | 160622556011554 |
oct | 22405705735607 |
9 | 4447455303547 |
10 | 1272100404103 |
11 | 450549572921 |
12 | 18665ba27407 |
13 | 92c5cc32109 |
14 | 457da093a2b |
15 | 231548e33bd |
hex | 1282f17bb87 |
1272100404103 has 4 divisors (see below), whose sum is σ = 1272269866840. Its totient is φ = 1271930941368.
The previous prime is 1272100404089. The next prime is 1272100404121. The reversal of 1272100404103 is 3014040012721.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1272100404103 - 29 = 1272100403591 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1272100404143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84720108 + ... + 84735121.
It is an arithmetic number, because the mean of its divisors is an integer number (318067466710).
Almost surely, 21272100404103 is an apocalyptic number.
1272100404103 is a deficient number, since it is larger than the sum of its proper divisors (169462737).
1272100404103 is an equidigital number, since it uses as much as digits as its factorization.
1272100404103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 169462736.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 1272100404103 its reverse (3014040012721), we get a palindrome (4286140416824).
The spelling of 1272100404103 in words is "one trillion, two hundred seventy-two billion, one hundred million, four hundred four thousand, one hundred three".
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