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1274144256013 is a prime number
BaseRepresentation
bin10010100010101000111…
…010100111000000001101
311111210210022012120100111
4102202220322213000031
5131333421412143023
62413200033200021
7161024324323516
oct22425072470015
94453708176314
101274144256013
114513a8241032
12186b30400011
13931c74c1345
14459516c5a0d
152322406900d
hex128a8ea700d

1274144256013 has 2 divisors, whose sum is σ = 1274144256014. Its totient is φ = 1274144256012.

The previous prime is 1274144255977. The next prime is 1274144256017. The reversal of 1274144256013 is 3106524414721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1192667120649 + 81477135364 = 1092093^2 + 285442^2 .

It is a cyclic number.

It is not a de Polignac number, because 1274144256013 - 217 = 1274144124941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1274144256017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 637072128006 + 637072128007.

It is an arithmetic number, because the mean of its divisors is an integer number (637072128007).

Almost surely, 21274144256013 is an apocalyptic number.

It is an amenable number.

1274144256013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1274144256013 is an equidigital number, since it uses as much as digits as its factorization.

1274144256013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 161280, while the sum is 40.

The spelling of 1274144256013 in words is "one trillion, two hundred seventy-four billion, one hundred forty-four million, two hundred fifty-six thousand, thirteen".