Base | Representation |
---|---|
bin | 10111110010001001… |
… | …01110001110100101 |
3 | 1012221212120010112221 |
4 | 23321010232032211 |
5 | 202122241334201 |
6 | 5511005312341 |
7 | 631264103401 |
oct | 137104561645 |
9 | 35855503487 |
10 | 12768699301 |
11 | 5462663856 |
12 | 25842656b1 |
13 | 12864a8697 |
14 | 891b5a101 |
15 | 4eaeb34a1 |
hex | 2f912e3a5 |
12768699301 has 4 divisors (see below), whose sum is σ = 12773894400. Its totient is φ = 12763504204.
The previous prime is 12768699299. The next prime is 12768699313. The reversal of 12768699301 is 10399686721.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10399686721 = 3881 ⋅2679641.
It is a cyclic number.
It is not a de Polignac number, because 12768699301 - 21 = 12768699299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12765699301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2593861 + ... + 2598778.
It is an arithmetic number, because the mean of its divisors is an integer number (3193473600).
Almost surely, 212768699301 is an apocalyptic number.
It is an amenable number.
12768699301 is a deficient number, since it is larger than the sum of its proper divisors (5195099).
12768699301 is an equidigital number, since it uses as much as digits as its factorization.
12768699301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5195098.
The product of its (nonzero) digits is 979776, while the sum is 52.
The spelling of 12768699301 in words is "twelve billion, seven hundred sixty-eight million, six hundred ninety-nine thousand, three hundred one".
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