Base | Representation |
---|---|
bin | 11101000111000111011000… |
… | …100001010011001101001011 |
3 | 121210022202210000021102112122 |
4 | 131013013120201103031023 |
5 | 113240140134030001124 |
6 | 1132145122115001455 |
7 | 35653013031002513 |
oct | 3507073041231513 |
9 | 553282700242478 |
10 | 128032312734539 |
11 | 3788222081a134 |
12 | 1243962a59928b |
13 | 565951a5994a5 |
14 | 2388b22d7c843 |
15 | ec063327e75e |
hex | 7471d885334b |
128032312734539 has 2 divisors, whose sum is σ = 128032312734540. Its totient is φ = 128032312734538.
The previous prime is 128032312734463. The next prime is 128032312734541. The reversal of 128032312734539 is 935437213230821.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-128032312734539 is a prime.
Together with 128032312734541, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (128032314734539) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64016156367269 + 64016156367270.
It is an arithmetic number, because the mean of its divisors is an integer number (64016156367270).
Almost surely, 2128032312734539 is an apocalyptic number.
128032312734539 is a deficient number, since it is larger than the sum of its proper divisors (1).
128032312734539 is an equidigital number, since it uses as much as digits as its factorization.
128032312734539 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6531840, while the sum is 53.
The spelling of 128032312734539 in words is "one hundred twenty-eight trillion, thirty-two billion, three hundred twelve million, seven hundred thirty-four thousand, five hundred thirty-nine".
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