Base | Representation |
---|---|
bin | 11101001000000010011111… |
… | …110110110010010001011111 |
3 | 121210112211121121111121110120 |
4 | 131020002133312302101133 |
5 | 113242210132330344233 |
6 | 1132234220355410023 |
7 | 35660421001515015 |
oct | 3510023766622137 |
9 | 553484547447416 |
10 | 128095786574943 |
11 | 378a7133086980 |
12 | 124499a38b3913 |
13 | 56624c4934035 |
14 | 238bc24d408b5 |
15 | ec20ea9734b3 |
hex | 74809fdb245f |
128095786574943 has 16 divisors (see below), whose sum is σ = 186551454585600. Its totient is φ = 77537847346880.
The previous prime is 128095786574923. The next prime is 128095786574953. The reversal of 128095786574943 is 349475687590821.
It is a cyclic number.
It is not a de Polignac number, because 128095786574943 - 213 = 128095786566751 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (128095786574923) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2399040363 + ... + 2399093756.
It is an arithmetic number, because the mean of its divisors is an integer number (11659465911600).
It is a 1-persistent number, because it is pandigital, but 2⋅128095786574943 = 256191573149886 is not.
Almost surely, 2128095786574943 is an apocalyptic number.
128095786574943 is a deficient number, since it is larger than the sum of its proper divisors (58455668010657).
128095786574943 is a wasteful number, since it uses less digits than its factorization.
128095786574943 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4798134942.
The product of its (nonzero) digits is 3657830400, while the sum is 78.
The spelling of 128095786574943 in words is "one hundred twenty-eight trillion, ninety-five billion, seven hundred eighty-six million, five hundred seventy-four thousand, nine hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •