Base | Representation |
---|---|
bin | 1011101001110000100101… |
… | …0011000000000011101111 |
3 | 1200100211010100000222000111 |
4 | 2322130021103000003233 |
5 | 3134403031103414022 |
6 | 43125434350440451 |
7 | 2461432244131615 |
oct | 272341123000357 |
9 | 50324110028014 |
10 | 12812043419887 |
11 | 409a614557178 |
12 | 152b087503127 |
13 | 71c22a7c40ca |
14 | 32416b6256b5 |
15 | 17340d6ad477 |
hex | ba7094c00ef |
12812043419887 has 2 divisors, whose sum is σ = 12812043419888. Its totient is φ = 12812043419886.
The previous prime is 12812043419881. The next prime is 12812043420049. The reversal of 12812043419887 is 78891434021821.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12812043419887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12812043419881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6406021709943 + 6406021709944.
It is an arithmetic number, because the mean of its divisors is an integer number (6406021709944).
Almost surely, 212812043419887 is an apocalyptic number.
12812043419887 is a deficient number, since it is larger than the sum of its proper divisors (1).
12812043419887 is an equidigital number, since it uses as much as digits as its factorization.
12812043419887 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6193152, while the sum is 58.
The spelling of 12812043419887 in words is "twelve trillion, eight hundred twelve billion, forty-three million, four hundred nineteen thousand, eight hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •