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12812043420049 is a prime number
BaseRepresentation
bin1011101001110000100101…
…0011000000000110010001
31200100211010100000222020111
42322130021103000012101
53134403031103420144
643125434350441321
72461432244132236
oct272341123000621
950324110028214
1012812043420049
11409a614557305
12152b087503241
1371c22a7c41c3
1432416b62578d
1517340d6ad534
hexba7094c0191

12812043420049 has 2 divisors, whose sum is σ = 12812043420050. Its totient is φ = 12812043420048.

The previous prime is 12812043419887. The next prime is 12812043420109. The reversal of 12812043420049 is 94002434021821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11271006701824 + 1541036718225 = 3357232^2 + 1241385^2 .

It is a cyclic number.

It is not a de Polignac number, because 12812043420049 - 217 = 12812043288977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12812043419993 and 12812043420020.

It is not a weakly prime, because it can be changed into another prime (12812043429049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6406021710024 + 6406021710025.

It is an arithmetic number, because the mean of its divisors is an integer number (6406021710025).

Almost surely, 212812043420049 is an apocalyptic number.

It is an amenable number.

12812043420049 is a deficient number, since it is larger than the sum of its proper divisors (1).

12812043420049 is an equidigital number, since it uses as much as digits as its factorization.

12812043420049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 110592, while the sum is 40.

The spelling of 12812043420049 in words is "twelve trillion, eight hundred twelve billion, forty-three million, four hundred twenty thousand, forty-nine".