Base | Representation |
---|---|
bin | 1011101001110000100101… |
… | …0011000000000100011011 |
3 | 1200100211010100000222002010 |
4 | 2322130021103000010123 |
5 | 3134403031103414211 |
6 | 43125434350441003 |
7 | 2461432244132010 |
oct | 272341123000433 |
9 | 50324110028063 |
10 | 12812043419931 |
11 | 409a614557208 |
12 | 152b087503163 |
13 | 71c22a7c4132 |
14 | 32416b625707 |
15 | 17340d6ad4a6 |
hex | ba7094c011b |
12812043419931 has 32 divisors (see below), whose sum is σ = 19680381370368. Its totient is φ = 7262213081760.
The previous prime is 12812043419887. The next prime is 12812043420049. The reversal of 12812043419931 is 13991434021821.
It is not a de Polignac number, because 12812043419931 - 26 = 12812043419867 is a prime.
It is a super-2 number, since 2×128120434199312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12812043415931) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14481586 + ... + 15340808.
It is an arithmetic number, because the mean of its divisors is an integer number (615011917824).
Almost surely, 212812043419931 is an apocalyptic number.
12812043419931 is a deficient number, since it is larger than the sum of its proper divisors (6868337950437).
12812043419931 is a wasteful number, since it uses less digits than its factorization.
12812043419931 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 864951.
The product of its (nonzero) digits is 373248, while the sum is 48.
The spelling of 12812043419931 in words is "twelve trillion, eight hundred twelve billion, forty-three million, four hundred nineteen thousand, nine hundred thirty-one".
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