12812043419930 has 8 divisors (see below), whose sum is σ = 23061678155892. Its totient is φ = 5124817367968.

The previous prime is 12812043419887. The next prime is 12812043420049. The reversal of 12812043419930 is 3991434021821.

It can be written as a sum of positive squares in 2 ways, for example, as 12136716120841 + 675327299089 = 3483779^2 + 821783^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×12812043419930² (a number of 27 digits) contains 22 as substring.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 640602170987 + ... + 640602171006.

Almost surely, 2^{12812043419930} is an apocalyptic number.

12812043419930 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12812043419930 is a deficient number, since it is larger than the sum of its proper divisors (10249634735962).

12812043419930 is a wasteful number, since it uses less digits than its factorization.

12812043419930 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1281204342000.

The product of its (nonzero) digits is 373248, while the sum is 47.

The spelling of 12812043419930 in words is "twelve trillion, eight hundred twelve billion, forty-three million, four hundred nineteen thousand, nine hundred thirty".