Search a number
-
+
1281641883997 is a prime number
BaseRepresentation
bin10010101001100111110…
…011110010100101011101
311112112010211022112101211
4102221213303302211131
5131444300310241442
62420440025304421
7161411165160316
oct22514763624535
94475124275354
101281641883997
114545a54819a2
12188483335111
1393b2092b7c7
144606337b60d
15235123cd617
hex12a67cf295d

1281641883997 has 2 divisors, whose sum is σ = 1281641883998. Its totient is φ = 1281641883996.

The previous prime is 1281641883953. The next prime is 1281641884009. The reversal of 1281641883997 is 7993881461821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1101169001956 + 180472882041 = 1049366^2 + 424821^2 .

It is a cyclic number.

It is not a de Polignac number, because 1281641883997 - 219 = 1281641359709 is a prime.

It is a super-3 number, since 3×12816418839973 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1281641883917) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 640820941998 + 640820941999.

It is an arithmetic number, because the mean of its divisors is an integer number (640820941999).

Almost surely, 21281641883997 is an apocalyptic number.

It is an amenable number.

1281641883997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1281641883997 is an equidigital number, since it uses as much as digits as its factorization.

1281641883997 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41803776, while the sum is 67.

The spelling of 1281641883997 in words is "one trillion, two hundred eighty-one billion, six hundred forty-one million, eight hundred eighty-three thousand, nine hundred ninety-seven".