Base | Representation |
---|---|
bin | 1011101010110110010010… |
… | …1001000100100000011101 |
3 | 1200102121102102200102101011 |
4 | 2322231210221010200131 |
5 | 3140204341441113432 |
6 | 43142211242015221 |
7 | 2462664042553132 |
oct | 272554451044035 |
9 | 50377372612334 |
10 | 12830755801117 |
11 | 40a7547175151 |
12 | 153282a1a7511 |
13 | 720c204aa437 |
14 | 3250248d0589 |
15 | 173b56382847 |
hex | bab64a4481d |
12830755801117 has 2 divisors, whose sum is σ = 12830755801118. Its totient is φ = 12830755801116.
The previous prime is 12830755801037. The next prime is 12830755801133. The reversal of 12830755801117 is 71110855703821.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9870725016441 + 2960030784676 = 3141771^2 + 1720474^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12830755801117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12830755801147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6415377900558 + 6415377900559.
It is an arithmetic number, because the mean of its divisors is an integer number (6415377900559).
Almost surely, 212830755801117 is an apocalyptic number.
It is an amenable number.
12830755801117 is a deficient number, since it is larger than the sum of its proper divisors (1).
12830755801117 is an equidigital number, since it uses as much as digits as its factorization.
12830755801117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 470400, while the sum is 49.
The spelling of 12830755801117 in words is "twelve trillion, eight hundred thirty billion, seven hundred fifty-five million, eight hundred one thousand, one hundred seventeen".
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