Base | Representation |
---|---|
bin | 1011101011100111001100… |
… | …0111110100110011001000 |
3 | 1200110212022100001001020221 |
4 | 2322321303013310303020 |
5 | 3140413233203134102 |
6 | 43152222041155424 |
7 | 2463640260444616 |
oct | 272716307646310 |
9 | 50425270031227 |
10 | 12843883646152 |
11 | 410207352a459 |
12 | 153529278bb74 |
13 | 7222331c1a90 |
14 | 32590c2186b6 |
15 | 174173b39637 |
hex | bae731f4cc8 |
12843883646152 has 32 divisors (see below), whose sum is σ = 25935007694400. Its totient is φ = 5927890837824.
The previous prime is 12843883646107. The next prime is 12843883646177. The reversal of 12843883646152 is 25164638834821.
It is a super-3 number, since 3×128438836461523 (a number of 40 digits) contains 333 as substring.
It is a Smith number, since the sum of its digits (61) coincides with the sum of the digits of its prime factors.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11876493 + ... + 12912739.
It is an arithmetic number, because the mean of its divisors is an integer number (810468990450).
Almost surely, 212843883646152 is an apocalyptic number.
It is an amenable number.
12843883646152 is an abundant number, since it is smaller than the sum of its proper divisors (13091124048248).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12843883646152 is a wasteful number, since it uses less digits than its factorization.
12843883646152 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1155445 (or 1155441 counting only the distinct ones).
The product of its digits is 53084160, while the sum is 61.
The spelling of 12843883646152 in words is "twelve trillion, eight hundred forty-three billion, eight hundred eighty-three million, six hundred forty-six thousand, one hundred fifty-two".
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