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12902117 is a prime number
BaseRepresentation
bin110001001101…
…111011100101
3220021111101012
4301031323211
511300331432
61140312005
7214444334
oct61157345
926244335
1012902117
117312608
1243a2605
1328997b7
1419dbd1b
1511eccb2
hexc4dee5

12902117 has 2 divisors, whose sum is σ = 12902118. Its totient is φ = 12902116.

The previous prime is 12902077. The next prime is 12902137. The reversal of 12902117 is 71120921.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12716356 + 185761 = 3566^2 + 431^2 .

It is an emirp because it is prime and its reverse (71120921) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12902117 - 26 = 12902053 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12902092 and 12902101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12902137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6451058 + 6451059.

It is an arithmetic number, because the mean of its divisors is an integer number (6451059).

Almost surely, 212902117 is an apocalyptic number.

It is an amenable number.

12902117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12902117 is an equidigital number, since it uses as much as digits as its factorization.

12902117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 23.

The square root of 12902117 is about 3591.9516978935. The cubic root of 12902117 is about 234.5418385894.

The spelling of 12902117 in words is "twelve million, nine hundred two thousand, one hundred seventeen".