Base | Representation |
---|---|
bin | 1011110000010110100100… |
… | …1000011001111101101000 |
3 | 1200202122111210200000122122 |
4 | 2330011221020121331220 |
5 | 3143232024010423330 |
6 | 43253451001410412 |
7 | 2502552326460224 |
oct | 274055110317550 |
9 | 50678453600578 |
10 | 12925320404840 |
11 | 4133663451608 |
12 | 154901b799a08 |
13 | 729b10ba575c |
14 | 329835b13784 |
15 | 17633d30e5e5 |
hex | bc169219f68 |
12925320404840 has 32 divisors (see below), whose sum is σ = 29558724537960. Its totient is φ = 5085371961600.
The previous prime is 12925320404819. The next prime is 12925320404869. The reversal of 12925320404840 is 4840402352921.
It can be written as a sum of positive squares in 4 ways, for example, as 8398902463396 + 4526417941444 = 2898086^2 + 2127538^2 .
It is a super-2 number, since 2×129253204048402 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12925320404791 and 12925320404800.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2648628791 + ... + 2648633670.
Almost surely, 212925320404840 is an apocalyptic number.
12925320404840 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12925320404840 is an abundant number, since it is smaller than the sum of its proper divisors (16633404133120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12925320404840 is a wasteful number, since it uses less digits than its factorization.
12925320404840 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5297262533 (or 5297262529 counting only the distinct ones).
The product of its (nonzero) digits is 552960, while the sum is 44.
The spelling of 12925320404840 in words is "twelve trillion, nine hundred twenty-five billion, three hundred twenty million, four hundred four thousand, eight hundred forty".
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