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12937025651117 is a prime number
BaseRepresentation
bin1011110001000010001011…
…0100011000000110101101
31200210202201120011010220112
42330100202310120012231
53143430012031313432
643303104301425405
72503445361434531
oct274204264300655
950722646133815
1012937025651117
11413861a792367
12154b34786b265
1372ac57c58399
1432a226525bc1
151767c5c5a7b2
hexbc422d181ad

12937025651117 has 2 divisors, whose sum is σ = 12937025651118. Its totient is φ = 12937025651116.

The previous prime is 12937025651087. The next prime is 12937025651167. The reversal of 12937025651117 is 71115652073921.

It is an a-pointer prime, because the next prime (12937025651167) can be obtained adding 12937025651117 to its sum of digits (50).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12753797992516 + 183227658601 = 3571246^2 + 428051^2 .

It is a cyclic number.

It is not a de Polignac number, because 12937025651117 - 214 = 12937025634733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12937025651167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6468512825558 + 6468512825559.

It is an arithmetic number, because the mean of its divisors is an integer number (6468512825559).

Almost surely, 212937025651117 is an apocalyptic number.

It is an amenable number.

12937025651117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12937025651117 is an equidigital number, since it uses as much as digits as its factorization.

12937025651117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 793800, while the sum is 50.

The spelling of 12937025651117 in words is "twelve trillion, nine hundred thirty-seven billion, twenty-five million, six hundred fifty-one thousand, one hundred seventeen".