Base | Representation |
---|---|
bin | 11000000110011101… |
… | …10110000110011101 |
3 | 1020101202020122212101 |
4 | 30003032312012131 |
5 | 202444404001044 |
6 | 5535534205101 |
7 | 635433514636 |
oct | 140316660635 |
9 | 36352218771 |
10 | 12939125149 |
11 | 553a887265 |
12 | 2611353791 |
13 | 12b28a9792 |
14 | 8aa64088d |
15 | 50ae29cd4 |
hex | 3033b619d |
12939125149 has 2 divisors, whose sum is σ = 12939125150. Its totient is φ = 12939125148.
The previous prime is 12939125131. The next prime is 12939125159. The reversal of 12939125149 is 94152193921.
12939125149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11748392100 + 1190733049 = 108390^2 + 34507^2 .
It is a cyclic number.
It is not a de Polignac number, because 12939125149 - 25 = 12939125117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12939125099 and 12939125108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12939125159) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6469562574 + 6469562575.
It is an arithmetic number, because the mean of its divisors is an integer number (6469562575).
Almost surely, 212939125149 is an apocalyptic number.
It is an amenable number.
12939125149 is a deficient number, since it is larger than the sum of its proper divisors (1).
12939125149 is an equidigital number, since it uses as much as digits as its factorization.
12939125149 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 174960, while the sum is 46.
The spelling of 12939125149 in words is "twelve billion, nine hundred thirty-nine million, one hundred twenty-five thousand, one hundred forty-nine".
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