Base | Representation |
---|---|
bin | 11000000110111000… |
… | …10011100000000011 |
3 | 1020101222212220202221 |
4 | 30003130103200003 |
5 | 203001304402233 |
6 | 5540141551511 |
7 | 635505511336 |
oct | 140334234003 |
9 | 36358786687 |
10 | 12942653443 |
11 | 5541877105 |
12 | 2612575597 |
13 | 12b3543725 |
14 | 8aacbc61d |
15 | 50b3c542d |
hex | 303713803 |
12942653443 has 2 divisors, whose sum is σ = 12942653444. Its totient is φ = 12942653442.
The previous prime is 12942653441. The next prime is 12942653461. The reversal of 12942653443 is 34435624921.
It is a weak prime.
It is an emirp because it is prime and its reverse (34435624921) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12942653443 - 21 = 12942653441 is a prime.
Together with 12942653441, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 12942653443.
It is not a weakly prime, because it can be changed into another prime (12942653441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6471326721 + 6471326722.
It is an arithmetic number, because the mean of its divisors is an integer number (6471326722).
Almost surely, 212942653443 is an apocalyptic number.
12942653443 is a deficient number, since it is larger than the sum of its proper divisors (1).
12942653443 is an equidigital number, since it uses as much as digits as its factorization.
12942653443 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 622080, while the sum is 43.
The spelling of 12942653443 in words is "twelve billion, nine hundred forty-two million, six hundred fifty-three thousand, four hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •